Find roots of polynomial $$ p(x) = x^2-18x+78 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 10.7321\\[1 em]x_2 &= 7.2679 \end{aligned} $$Explanation
The solutions of $ x^2-18x+78 = 0 $ are: $ x = 9-\sqrt{ 3 } ~ \text{and} ~ x = 9+\sqrt{ 3 }$.
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