Find roots of polynomial $$ p(x) = x^2-18x+54 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 14.1962\\[1 em]x_2 &= 3.8038 \end{aligned} $$Explanation
The solutions of $ x^2-18x+54 = 0 $ are: $ x = 9-3 \sqrt{ 3 } ~ \text{and} ~ x = 9+3 \sqrt{ 3 }$.
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