Find roots of polynomial $$ p(x) = x^2-10x+26 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 5+i\\[1 em]x_2 &= 5-i \end{aligned} $$Explanation
The solutions of $ x^2-10x+26 = 0 $ are: $ x = 5+i ~ \text{and} ~ x = 5-i$.
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