Find roots of polynomial $$ p(x) = x^{10}-10x^2+4 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 0.6333\\[1 em]x_2 &= -0.6333\\[1 em]x_3 &= 1.2883\\[1 em]x_4 &= -1.2883\\[1 em]x_5 &= -0.9212+0.9724i\\[1 em]x_6 &= -0.9212-0.9724i\\[1 em]x_7 &= 0.9212+0.9724i\\[1 em]x_8 &= 0.9212-0.9724i\\[1 em]x_9 &= 1.3663i\\[1 em]x_{10} &= -1.3663i \end{aligned} $$Explanation
Polynomial $ x^{10}-10x^2+4 $ has no rational roots that can be found using Rational Root Test, so the roots were found using Newton method.
This page was created using
Polynomial Roots Calculator