Find roots of polynomial $$ p(x) = t^2-15 $$
Answer
The roots of polynomial $ p(t) $ are:
$$ \begin{aligned}t_1 &= \sqrt{ 15 }\\[1 em]t_2 &= -\sqrt{ 15 } \end{aligned} $$Explanation
The solutions of $ t^2-15 = 0 $ are: $ t = -\sqrt{ 15 } ~ \text{and} ~ t = \sqrt{ 15 }$.
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