Find roots of polynomial $$ p(x) = s^2+558s+948137 $$
Answer
The roots of polynomial $ p(s) $ are:
$$ \begin{aligned}s_1 &= -279+2 \sqrt{ 217574 }i\\[1 em]s_2 &= -279-2 \sqrt{ 217574 }i \end{aligned} $$Explanation
The solutions of $ s^2+558s+948137 = 0 $ are: $ s = -279+2 \sqrt{ 217574 }i ~ \text{and} ~ s = -279-2 \sqrt{ 217574 }i$.
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