Find roots of polynomial $$ p(x) = s^2+2500s+125000 $$
Answer
The roots of polynomial $ p(s) $ are:
$$ \begin{aligned}s_1 &= -51.0421\\[1 em]s_2 &= -2448.9579 \end{aligned} $$Explanation
The solutions of $ s^2+2500s+125000 = 0 $ are: $ s = -1250-250 \sqrt{ 23 } ~ \text{and} ~ s = -1250+250 \sqrt{ 23 }$.
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