Find roots of polynomial $$ p(x) = s^2+10s+26 $$
Answer
The roots of polynomial $ p(s) $ are:
$$ \begin{aligned}s_1 &= -5+i\\[1 em]s_2 &= -5-i \end{aligned} $$Explanation
The solutions of $ s^2+10s+26 = 0 $ are: $ s = -5+i ~ \text{and} ~ s = -5-i$.
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