Find roots of polynomial $$ p(x) = r^3-3r^2+7r-8 $$
Answer
The roots of polynomial $ p(r) $ are:
$$ \begin{aligned}r_1 &= 1.6736\\[1 em]r_2 &= 0.6632+2.0833i\\[1 em]r_3 &= 0.6632-2.0833i \end{aligned} $$Explanation
Polynomial $ r^3-3r^2+7r-8 $ has no rational roots that can be found using Rational Root Test, so the roots were found using qubic formulas.
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