Find roots of polynomial $$ p(x) = r^2-5r+6 $$
Answer
The roots of polynomial $ p(r) $ are:
$$ \begin{aligned}r_1 &= 3\\[1 em]r_2 &= 2 \end{aligned} $$Explanation
The solutions of $ r^2-5r+6 = 0 $ are: $ r = 2 ~ \text{and} ~ r = 3$.
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