Find roots of polynomial $$ p(x) = r^2-4r+1 $$
Answer
The roots of polynomial $ p(r) $ are:
$$ \begin{aligned}r_1 &= 3.7321\\[1 em]r_2 &= 0.2679 \end{aligned} $$Explanation
The solutions of $ r^2-4r+1 = 0 $ are: $ r = 2-\sqrt{ 3 } ~ \text{and} ~ r = 2+\sqrt{ 3 }$.
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