Find roots of polynomial $$ p(x) = p^2-7p+6 $$
Answer
The roots of polynomial $ p(p) $ are:
$$ \begin{aligned}p_1 &= 6\\[1 em]p_2 &= 1 \end{aligned} $$Explanation
The solutions of $ p^2-7p+6 = 0 $ are: $ p = 1 ~ \text{and} ~ p = 6$.
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