Find roots of polynomial $$ p(x) = m^2+7m-18 $$
Answer
The roots of polynomial $ p(m) $ are:
$$ \begin{aligned}m_1 &= 2\\[1 em]m_2 &= -9 \end{aligned} $$Explanation
The solutions of $ m^2+7m-18 = 0 $ are: $ m = -9 ~ \text{and} ~ m = 2$.
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