Find roots of polynomial $$ p(x) = m^2+2m+4 $$
Answer
The roots of polynomial $ p(m) $ are:
$$ \begin{aligned}m_1 &= -1+\sqrt{ 3 }i\\[1 em]m_2 &= -1-\sqrt{ 3 }i \end{aligned} $$Explanation
The solutions of $ m^2+2m+4 = 0 $ are: $ m = -1+\sqrt{ 3 }i ~ \text{and} ~ m = -1-\sqrt{ 3 }i$.
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