Find roots of polynomial $$ p(x) = m^2+14m+9 $$
Answer
The roots of polynomial $ p(m) $ are:
$$ \begin{aligned}m_1 &= -0.6754\\[1 em]m_2 &= -13.3246 \end{aligned} $$Explanation
The solutions of $ m^2+14m+9 = 0 $ are: $ m = -7-2 \sqrt{ 10 } ~ \text{and} ~ m = -7+2 \sqrt{ 10 }$.
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