Find roots of polynomial $$ p(x) = m^2-3m-2 $$
Answer
The roots of polynomial $ p(m) $ are:
$$ \begin{aligned}m_1 &= 3.5616\\[1 em]m_2 &= -0.5616 \end{aligned} $$Explanation
The solutions of $ m^2-3m-2 = 0 $ are: $ m = \dfrac{ 3 }{ 2 }-\dfrac{\sqrt{ 17 }}{ 2 } ~ \text{and} ~ m = \dfrac{ 3 }{ 2 }+\dfrac{\sqrt{ 17 }}{ 2 }$.
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