Find roots of polynomial $$ p(x) = m^2-\frac{2}{3}m+\frac{1}{9} $$
Answer
The root of polynomial $ p(m) $ is:
$$ \begin{aligned}m &= \frac{ 1 }{ 3 } \end{aligned} $$Explanation
Step 1:
Get rid of fractions by multipling equation by $ \color{blue}{ 9 } $.
$$ \begin{aligned} m^2-\frac{2}{3}m+\frac{1}{9} & = 0 ~~~ / \cdot \color{blue}{ 9 } \\[1 em] 9m^2-6m+1 & = 0 \end{aligned} $$Step 2:
The solution of $ ~ 9m^2-6m+1 = 0 ~$ is $~ m = \dfrac{ 1 }{ 3 } ~$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
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