Find roots of polynomial $$ p(x) = d^2+4d+40 $$
Answer
The roots of polynomial $ p(d) $ are:
$$ \begin{aligned}d_1 &= -2+6i\\[1 em]d_2 &= -2-6i \end{aligned} $$Explanation
The solutions of $ d^2+4d+40 = 0 $ are: $ d = -2+6i ~ \text{and} ~ d = -2-6i$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
This page was created using
Polynomial Roots Calculator