Find roots of polynomial $$ p(x) = d^2-4d+7 $$
Answer
The roots of polynomial $ p(d) $ are:
$$ \begin{aligned}d_1 &= 2+\sqrt{ 3 }i\\[1 em]d_2 &= 2-\sqrt{ 3 }i \end{aligned} $$Explanation
The solutions of $ d^2-4d+7 = 0 $ are: $ d = 2+\sqrt{ 3 }i ~ \text{and} ~ d = 2-\sqrt{ 3 }i$.
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