Find roots of polynomial $$ p(x) = d^2-4 $$
Answer
The roots of polynomial $ p(d) $ are:
$$ \begin{aligned}d_1 &= 2\\[1 em]d_2 &= -2 \end{aligned} $$Explanation
The solutions of $ d^2-4 = 0 $ are: $ d = -2 ~ \text{and} ~ d = 2$.
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