Find roots of polynomial $$ p(x) = b^2-7b-30 $$
Answer
The roots of polynomial $ p(b) $ are:
$$ \begin{aligned}b_1 &= 10\\[1 em]b_2 &= -3 \end{aligned} $$Explanation
The solutions of $ b^2-7b-30 = 0 $ are: $ b = -3 ~ \text{and} ~ b = 10$.
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