The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= \frac{ 2 }{ 3 }i\\[1 em]x_2 &= -\frac{ 2 }{ 3 }i \end{aligned} $$The solutions of $ 9x^2+4 = 0 $ are: $ x = \dfrac{ 2 }{ 3 } i ~ \text{and} ~ x = -\dfrac{ 2 }{ 3 } i $.
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