Find roots of polynomial $$ p(x) = 9x^2+12x-1 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 0.0787\\[1 em]x_2 &= -1.412 \end{aligned} $$Explanation
The solutions of $ 9x^2+12x-1 = 0 $ are: $ x = -\dfrac{ 2 }{ 3 }-\dfrac{\sqrt{ 5 }}{ 3 } ~ \text{and} ~ x = -\dfrac{ 2 }{ 3 }+\dfrac{\sqrt{ 5 }}{ 3 }$.
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