Find roots of polynomial $$ p(x) = 9x^2-4x+5 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= \frac{ 2 }{ 9 }+\frac{\sqrt{ 41 }}{ 9 }i\\[1 em]x_2 &= \frac{ 2 }{ 9 }- \frac{\sqrt{ 41 }}{ 9 }i \end{aligned} $$Explanation
The solutions of $ 9x^2-4x+5 = 0 $ are: $ x = \dfrac{ 2 }{ 9 }+\dfrac{\sqrt{ 41 }}{ 9 }i ~ \text{and} ~ x = \dfrac{ 2 }{ 9 }-\dfrac{\sqrt{ 41 }}{ 9 }i$.
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