Find roots of polynomial $$ p(x) = 9x^2-16x-8 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 2.1847\\[1 em]x_2 &= -0.4069 \end{aligned} $$Explanation
The solutions of $ 9x^2-16x-8 = 0 $ are: $ x = \dfrac{ 8 }{ 9 }-\dfrac{ 2 \sqrt{ 34}}{ 9 } ~ \text{and} ~ x = \dfrac{ 8 }{ 9 }+\dfrac{ 2 \sqrt{ 34}}{ 9 }$.
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