Find roots of polynomial $$ p(x) = 9r^2-35r-4 $$
Answer
The roots of polynomial $ p(r) $ are:
$$ \begin{aligned}r_1 &= 4\\[1 em]r_2 &= -\frac{ 1 }{ 9 } \end{aligned} $$Explanation
The solutions of $ 9r^2-35r-4 = 0 $ are: $ r = -\dfrac{ 1 }{ 9 } ~ \text{and} ~ r = 4$.
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