Find roots of polynomial $$ p(x) = 96x^2+44x-21 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= \frac{ 7 }{ 24 }\\[1 em]x_2 &= -\frac{ 3 }{ 4 } \end{aligned} $$Explanation
The solutions of $ 96x^2+44x-21 = 0 $ are: $ x = -\dfrac{ 3 }{ 4 } ~ \text{and} ~ x = \dfrac{ 7 }{ 24 }$.
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