Find roots of polynomial $$ p(x) = 96x^2-2x-7 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 0.2806\\[1 em]x_2 &= -0.2598 \end{aligned} $$Explanation
The solutions of $ 96x^2-2x-7 = 0 $ are: $ x = \dfrac{ 1 }{ 96 }-\dfrac{\sqrt{ 673 }}{ 96 } ~ \text{and} ~ x = \dfrac{ 1 }{ 96 }+\dfrac{\sqrt{ 673 }}{ 96 }$.
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