Find roots of polynomial $$ p(x) = 91x^2+182x-350 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 1.2014\\[1 em]x_2 &= -3.2014 \end{aligned} $$Explanation
The solutions of $ 91x^2+182x-350 = 0 $ are: $ x = -1-\dfrac{ 3 \sqrt{ 91}}{ 13 } ~ \text{and} ~ x = -1+\dfrac{ 3 \sqrt{ 91}}{ 13 }$.
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