Find roots of polynomial $$ p(x) = 8x^2-60x+108 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= \frac{ 9 }{ 2 }\\[1 em]x_2 &= 3 \end{aligned} $$Explanation
The solutions of $ 8x^2-60x+108 = 0 $ are: $ x = 3 ~ \text{and} ~ x = \dfrac{ 9 }{ 2 }$.
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