Find roots of polynomial $$ p(x) = 8x^2-11x+10 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= \frac{ 11 }{ 16 }+\frac{\sqrt{ 199 }}{ 16 }i\\[1 em]x_2 &= \frac{ 11 }{ 16 }- \frac{\sqrt{ 199 }}{ 16 }i \end{aligned} $$Explanation
The solutions of $ 8x^2-11x+10 = 0 $ are: $ x = \dfrac{ 11 }{ 16 }+\dfrac{\sqrt{ 199 }}{ 16 }i ~ \text{and} ~ x = \dfrac{ 11 }{ 16 }-\dfrac{\sqrt{ 199 }}{ 16 }i$.
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