Find roots of polynomial $$ p(x) = 80x^2-32x+4 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= \frac{ 1 }{ 5 }+\frac{ 1 }{ 10 }i\\[1 em]x_2 &= \frac{ 1 }{ 5 }-\frac{ 1 }{ 10 }i \end{aligned} $$Explanation
The solutions of $ 80x^2-32x+4 = 0 $ are: $ x = \dfrac{ 1 }{ 5 }+\dfrac{ 1 }{ 10 }i ~ \text{and} ~ x = \dfrac{ 1 }{ 5 }-\dfrac{ 1 }{ 10 }i$.
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