Find roots of polynomial $$ p(x) = 7y^2+37y-152 $$
Answer
The roots of polynomial $ p(y) $ are:
$$ \begin{aligned}y_1 &= \frac{ 19 }{ 7 }\\[1 em]y_2 &= -8 \end{aligned} $$Explanation
The solutions of $ 7y^2+37y-152 = 0 $ are: $ y = -8 ~ \text{and} ~ y = \dfrac{ 19 }{ 7 }$.
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