Find roots of polynomial $$ p(x) = 7x^2-4x-2 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 0.8918\\[1 em]x_2 &= -0.3204 \end{aligned} $$Explanation
The solutions of $ 7x^2-4x-2 = 0 $ are: $ x = \dfrac{ 2 }{ 7 }-\dfrac{ 3 \sqrt{ 2}}{ 7 } ~ \text{and} ~ x = \dfrac{ 2 }{ 7 }+\dfrac{ 3 \sqrt{ 2}}{ 7 }$.
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