Find roots of polynomial $$ p(x) = 72x^2-17x+10 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= \frac{ 17 }{ 144 }+\frac{\sqrt{ 2591 }}{ 144 }i\\[1 em]x_2 &= \frac{ 17 }{ 144 }- \frac{\sqrt{ 2591 }}{ 144 }i \end{aligned} $$Explanation
The solutions of $ 72x^2-17x+10 = 0 $ are: $ x = \dfrac{ 17 }{ 144 }+\dfrac{\sqrt{ 2591 }}{ 144 }i ~ \text{and} ~ x = \dfrac{ 17 }{ 144 }-\dfrac{\sqrt{ 2591 }}{ 144 }i$.
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