The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 0\\[1 em]x_2 &= -0.8455\\[1 em]x_3 &= -2.4303\\[1 em]x_4 &= 0.3879+0.5798i\\[1 em]x_5 &= 0.3879-0.5798i \end{aligned} $$Step 1:
Factor out $ \color{blue}{ 3x }$ from $ 6x^5+15x^4+6x $ and solve two separate equations:
$$ \begin{aligned} 6x^5+15x^4+6x & = 0\\[1 em] \color{blue}{ 3x }\cdot ( 2x^4+5x^3+2 ) & = 0 \\[1 em] \color{blue}{ 3x = 0} ~~ \text{or} ~~ 2x^4+5x^3+2 & = 0 \end{aligned} $$One solution is $ \color{blue}{ x = 0 } $. Use second equation to find the remaining roots.
Step 2:
Polynomial $ 2x^4+5x^3+2 $ has no rational roots that can be found using Rational Root Test, so the roots were found using quartic formulas.