Find roots of polynomial $$ p(x) = 6x^2+27 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= \frac{ 3 \sqrt{ 2}}{ 2 }i\\[1 em]x_2 &= -3 \frac{\sqrt{ 2 }}{ 2 }i \end{aligned} $$Explanation
The solutions of $ 6x^2+27 = 0 $ are: $ x = \dfrac{ 3 \sqrt{ 2}}{ 2 } i ~ \text{and} ~ x = -3 \dfrac{\sqrt{ 2 }}{ 2 } i $.
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