Find roots of polynomial $$ p(x) = 6x^2+11x^2-36x-9 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 2.3435\\[1 em]x_2 &= -0.2259 \end{aligned} $$Explanation
Step 1:
Combine like terms:
$$ \color{blue}{6x^2} + \color{blue}{11x^2} -36x-9 = \color{blue}{17x^2} -36x-9 $$Step 2:
The solutions of $ 17x^2-36x-9 = 0 $ are: $ x = \dfrac{ 18 }{ 17 }-\dfrac{ 3 \sqrt{ 53}}{ 17 } ~ \text{and} ~ x = \dfrac{ 18 }{ 17 }+\dfrac{ 3 \sqrt{ 53}}{ 17 }$.
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