Find roots of polynomial $$ p(x) = 6x^2+10x+1 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= -0.1069\\[1 em]x_2 &= -1.5598 \end{aligned} $$Explanation
The solutions of $ 6x^2+10x+1 = 0 $ are: $ x = -\dfrac{ 5 }{ 6 }-\dfrac{\sqrt{ 19 }}{ 6 } ~ \text{and} ~ x = -\dfrac{ 5 }{ 6 }+\dfrac{\sqrt{ 19 }}{ 6 }$.
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