Find roots of polynomial $$ p(x) = 6x^2-5x+4 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= \frac{ 5 }{ 12 }+\frac{\sqrt{ 71 }}{ 12 }i\\[1 em]x_2 &= \frac{ 5 }{ 12 }- \frac{\sqrt{ 71 }}{ 12 }i \end{aligned} $$Explanation
The solutions of $ 6x^2-5x+4 = 0 $ are: $ x = \dfrac{ 5 }{ 12 }+\dfrac{\sqrt{ 71 }}{ 12 }i ~ \text{and} ~ x = \dfrac{ 5 }{ 12 }-\dfrac{\sqrt{ 71 }}{ 12 }i$.
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