Find roots of polynomial $$ p(x) = 6x^2-24x+40 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 2+\frac{ 2 \sqrt{ 6}}{ 3 }i\\[1 em]x_2 &= 2-2 \frac{\sqrt{ 6 }}{ 3 }i \end{aligned} $$Explanation
The solutions of $ 6x^2-24x+40 = 0 $ are: $ x = 2+\dfrac{ 2 \sqrt{ 6}}{ 3 }i ~ \text{and} ~ x = 2-\dfrac{ 2 \sqrt{ 6}}{ 3 }i$.
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