Find roots of polynomial $$ p(x) = 6t^2-36t-96 $$
Answer
The roots of polynomial $ p(t) $ are:
$$ \begin{aligned}t_1 &= 8\\[1 em]t_2 &= -2 \end{aligned} $$Explanation
The solutions of $ 6t^2-36t-96 = 0 $ are: $ t = -2 ~ \text{and} ~ t = 8$.
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