Find roots of polynomial $$ p(x) = 5x^2+80x-283 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 2.9818\\[1 em]x_2 &= -18.9818 \end{aligned} $$Explanation
The solutions of $ 5x^2+80x-283 = 0 $ are: $ x = -8-\dfrac{ 3 \sqrt{ 335}}{ 5 } ~ \text{and} ~ x = -8+\dfrac{ 3 \sqrt{ 335}}{ 5 }$.
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