Find roots of polynomial $$ p(x) = 5x^2-49x+18 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 9.4177\\[1 em]x_2 &= 0.3823 \end{aligned} $$Explanation
The solutions of $ 5x^2-49x+18 = 0 $ are: $ x = \dfrac{ 49 }{ 10 }-\dfrac{\sqrt{ 2041 }}{ 10 } ~ \text{and} ~ x = \dfrac{ 49 }{ 10 }+\dfrac{\sqrt{ 2041 }}{ 10 }$.
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