Find roots of polynomial $$ p(x) = 5x^2-20x-476 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 11.9599\\[1 em]x_2 &= -7.9599 \end{aligned} $$Explanation
The solutions of $ 5x^2-20x-476 = 0 $ are: $ x = 2-\dfrac{ 4 \sqrt{ 155}}{ 5 } ~ \text{and} ~ x = 2+\dfrac{ 4 \sqrt{ 155}}{ 5 }$.
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