Find roots of polynomial $p (x) = 5 x^{2} - 19 x - 4$

Answer

The roots of polynomial $p (x)$ are:
$x_{1} x_{2} = 4 = - \frac{1}{5}$

Explanation

The solutions of $5 x^{2} - 19 x - 4 = 0$ are: $x = - \frac{1}{5} and x = 4$ .

You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.

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Find roots of polynomial p(x)=5x2−19x−4

The roots of polynomial p(x) are: x1​x2​​=4=−51​​

Find roots of polynomial $p (x) = 5 x^{2} - 19 x - 4$

The roots of polynomial $p (x)$ are:
$x_{1} x_{2} = 4 = - \frac{1}{5}$