Find roots of polynomial $$ p(x) = 5x^2-19x-4 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 4\\[1 em]x_2 &= -\frac{ 1 }{ 5 } \end{aligned} $$Explanation
The solutions of $ 5x^2-19x-4 = 0 $ are: $ x = -\dfrac{ 1 }{ 5 } ~ \text{and} ~ x = 4$.
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