The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 2\\[1 em]x_2 &= \frac{ 6 }{ 5 } \end{aligned} $$The solutions of $ 5x^2-16x+12 = 0 $ are: $ x = \dfrac{ 6 }{ 5 } ~ \text{and} ~ x = 2$.
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