Find roots of polynomial $$ p(x) = 5t^2-82t+160 $$
Answer
The roots of polynomial $ p(t) $ are:
$$ \begin{aligned}t_1 &= 14.1363\\[1 em]t_2 &= 2.2637 \end{aligned} $$Explanation
The solutions of $ 5t^2-82t+160 = 0 $ are: $ t = \dfrac{ 41 }{ 5 }-\dfrac{\sqrt{ 881 }}{ 5 } ~ \text{and} ~ t = \dfrac{ 41 }{ 5 }+\dfrac{\sqrt{ 881 }}{ 5 }$.
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