Find roots of polynomial $$ p(x) = 4x^4-35x^3+71x^2-4x+6 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 3.1272\\[1 em]x_2 &= 5.6084\\[1 em]x_3 &= 0.0072+0.2924i\\[1 em]x_4 &= 0.0072-0.2924i \end{aligned} $$Explanation
Polynomial $ 4x^4-35x^3+71x^2-4x+6 $ has no rational roots that can be found using Rational Root Test, so the roots were found using quartic formulas.
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