Find roots of polynomial $$ p(x) = 4x^2+18x^2+10x-1 $$
Answer
The roots of polynomial $ p(x) $ are:
$$ \begin{aligned}x_1 &= 0.0843\\[1 em]x_2 &= -0.5389 \end{aligned} $$Explanation
Step 1:
Combine like terms:
$$ \color{blue}{4x^2} + \color{blue}{18x^2} +10x-1 = \color{blue}{22x^2} +10x-1 $$Step 2:
The solutions of $ 22x^2+10x-1 = 0 $ are: $ x = -\dfrac{ 5 }{ 22 }-\dfrac{\sqrt{ 47 }}{ 22 } ~ \text{and} ~ x = -\dfrac{ 5 }{ 22 }+\dfrac{\sqrt{ 47 }}{ 22 }$.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this quadratic equation.
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